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2019-10-16标???o 陏??a???

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2019-05-07??AV??AV????标???o 陏??a???

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2019-05-07标???o 陏??a???

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??'???? ????1?o?'陏??驞1????? 1.??a??陏???'oD殛y???= 2.殍??陏???蜿??陏??? 3.??'????????'陏??髚??????篾? ??T ????2?o?'陏????????? 4.?'陏?梵 5.??a?'陏?? [???徼???]

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2019-05-07标???o 陏??a???

?鄖??? 鄖1.??'陏?'?D殛y???蜿?陏a?????a ????o??az?????a12??'陏???????a?陏??? . 鄖2.?'陏z=???1+z+z2????; ????o??a?'陏??? 鄖3.殍?'陏z??|z+|+|z-| = 2???髚z++ [???徼???]

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2019-05-07标???o 陏??a???

??'???? 1.殍?騙_________ 2. o?陏?R?????o?陏????????o?陏???,?蜿?陏???????ш? 3.???????????ш? 4.?o?陏?????????'????D?????3?????????a 5.?????? [???徼???]

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2019-05-07标???o 陏??a???

??'???? ????87????'o?o?陏????陏 1.??????'|???D???3?a____________?? 2.??ao?陏o?????'|???D???????DD???=________. 3.(?t????o????)殍o?陏 (??)????????鱀?;(?) [???徼???]

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1. 包o? 1???左?? ?騛?o驞?????(1)A?B???2????;(2)A?B?????o??? '??:??o?A2?包o?篾??o?B???o?B2?包o???o?A??作AB?駼A 2.2?o??o??a??????o??D??????????a 1??:????? [???徼???]

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陏?????Х??1o??'??辁2?D??髚??3?1?穙??D嘧?????鑩陏??????'?膀a??????????'????Y?? ?a?????? ????o???????????o??a?????D?????o???表??法??3??????阛 [???徼???]

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2019-05-07标???o 陏??a???

1.??法3?2? (1)??法??o????3霥?蝽? ?1y???a??????觎a1y3祗?2???????(????t?a?'??3熳??a??觎a)??????法??????????a??法??o???? ?1y?????2???????-帔悫1y殍 [???徼???]

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陏?3????'2?2????????瓯?靉?????????????a?????3??2???樽????2騛??鷒?左????-蝌???????1??'??a???????1?髚??|2?????1??????―?????1????'篁a [???徼???]

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2019-05-07标???o 陏??a???

?????? ??'?????法????璞桕y酓???皀??o?o Sn=a1+a1q+a1q2+ +a1qn-1?? ?3?q???oqSn=a1q+a1q2+a1q3+ +a1qn?? ???????(1-q)Sn=a1-a1qn?? Sn=(q 1). ???粪? (1)箝an+1=qan [???徼???]

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2019-05-07??AV??AV????标???o 陏??a???

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1.陏酓???? '??'?D??酓???酓陏?D?陏酓??陏酓?D???????陏???D?陏酓????. (1)'箨y酓???轵??'3???陏酓??陏?'??'?D??酓?????1?组3殛y酓??陏?囗?????酓'?D2???????'? [???徼???]

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2019-05-07??AV??AV????标???o 陏??a???

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2019-05-07??AV??AV????标???o 陏??a???

鑩??o?陏?t???1???2?' ???o1?? sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB tan(A+B)=(tanA+tanB)/(1-ta [???徼???]

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2019-05-07标???o 陏??a???

鑩??o?陏?t???1???2?' ???o1?? sin(A+B)=sinAcosB+cosAsinB sin(A-B)=sinAcosB-sinBcosA cos(A+B)=cosAcosB-sinAsinB cos(A-B)=cosAcosB+sinAsinB tan(A+B)=(tanA+tanB)/(1-ta [???徼???]

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2019-05-07标???o 陏??a???

鑩??o?陏?a?????o???鑩??o?陏1?? sin = ????? / D北? cos = ??狷? / D北? tan = ????? / ??狷? cot = ??狷? / ????? ???1?? Sin2A=2SinA?CosA Cos2A=CosA^2-SinA [???徼???]

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2019-05-07??AV??AV????标???o 陏??a???

1.????D标???D??????????3礻???????騛??2?'???????? 2.??????标?衢??????????????3?轵?囗?a?a????2?騛睃???标????????标?衢?????????0??蜞?a????? [???徼???]

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2019-05-07标???o 陏??a???

鑩??o?陏cos1??驞cosA=(b^2+c^2-a^2)/2bc??cosB=(a^2+c^2-b^2)/2ac??cosC=(a^2+b^2-c^2)/2ab??? 鑩??o?陏cos1??表 鑩??o?陏cos陏?? cos0 =1??cos15 =? 6+ 2??/4??cos30 = 3/2 cos [???徼???]

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2019-05-07??AV??AV????标???o 陏??a???

'?y?騩?陏?'筻?騩?陏????篁?[-1??1]??'?y?Do?陏o矸'筻?Do?陏????篁?R??'?y??o?陏o矸'筻??o?陏????篁??- ??-1]U[1??+ ???? '鑩??o?陏??篁 1??'鑩??o?陏1?? y??arc [???徼???]

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2019-05-07标???o 陏??a???

?蜥?????3?a*b1???oa*b=|a|*|b|*sin ??sin?a??b???D???????[0, ]???蜥??y|c|=|a b|=|a||b|sin a??b ????3???D?蜥?????y??陏??y???????蜥?o??眚????蜥?????蟀??3???3? [???徼???]

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2019-05-07??AV??AV????标???o 陏??a???

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